(8x^2)-16x+8=0

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Solution for (8x^2)-16x+8=0 equation: 



(8x^2)-16x+8=0

a = 8; b = -16; c = +8;
Δ = b2-4ac
Δ = -162-4·8·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{16}=1$

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